한쪽 연결고리 이상 select * from sales s, customers c where s.customer_id = c.customer_id X O -- index 유무 and s.saledate like '2010%' --> 10만건, saledate index 존재 and c.last_name = 'Lewis'; --> 10건, last_name index 존재 select statement nested loop table access (sales) index (saledate idx) table access (customers) index (customer_id idx) 양쪽 연결고리 정상 create index sales_customer_id_idx on sales(customer_id); ..